z^2+2(1-2i)z+2=0

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Solution for z^2+2(1-2i)z+2=0 equation:


Simplifying
z2 + 2(1 + -2i) * z + 2 = 0

Reorder the terms for easier multiplication:
z2 + 2z(1 + -2i) + 2 = 0
z2 + (1 * 2z + -2i * 2z) + 2 = 0

Reorder the terms:
z2 + (-4iz + 2z) + 2 = 0
z2 + (-4iz + 2z) + 2 = 0

Reorder the terms:
2 + -4iz + 2z + z2 = 0

Solving
2 + -4iz + 2z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -4iz + 2z + -2 + z2 = 0 + -2

Reorder the terms:
2 + -2 + -4iz + 2z + z2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -4iz + 2z + z2 = 0 + -2
-4iz + 2z + z2 = 0 + -2

Combine like terms: 0 + -2 = -2
-4iz + 2z + z2 = -2

Add '-2z' to each side of the equation.
-4iz + 2z + -2z + z2 = -2 + -2z

Combine like terms: 2z + -2z = 0
-4iz + 0 + z2 = -2 + -2z
-4iz + z2 = -2 + -2z

Add '-1z2' to each side of the equation.
-4iz + z2 + -1z2 = -2 + -2z + -1z2

Combine like terms: z2 + -1z2 = 0
-4iz + 0 = -2 + -2z + -1z2
-4iz = -2 + -2z + -1z2

Divide each side by '-4z'.
i = 0.5z-1 + 0.5 + 0.25z

Simplifying
i = 0.5z-1 + 0.5 + 0.25z

Reorder the terms:
i = 0.5 + 0.5z-1 + 0.25z

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